f(x)=log1/2(1-sinx)+log1/2(1+sinx) 那么f(π/3) =1/2是下标
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![f(x)=log1/2(1-sinx)+log1/2(1+sinx) 那么f(π/3) =1/2是下标](/uploads/image/z/5176869-69-9.jpg?t=f%EF%BC%88x%EF%BC%89%3Dlog1%2F2%EF%BC%881-sinx%EF%BC%89%2Blog1%2F2%281%2Bsinx%29+%E9%82%A3%E4%B9%88f%EF%BC%88%CF%80%2F3%EF%BC%89+%3D1%2F2%E6%98%AF%E4%B8%8B%E6%A0%87)
f(x)=log1/2(1-sinx)+log1/2(1+sinx) 那么f(π/3) =1/2是下标
f(x)=log1/2(1-sinx)+log1/2(1+sinx) 那么f(π/3) =
1/2是下标
f(x)=log1/2(1-sinx)+log1/2(1+sinx) 那么f(π/3) =1/2是下标
f(x)=log1/2(1-sinx)+log1/2(1+sinx)
=log(1/2)(1-sin^2 x)
=log1/2 (cosx)^2
故f(π/3)=2