(5)某温度下,H2(g)+Br2(g)==2HBr(g),达到平衡时,c(H2)=0.5mol/L,c(Br2)=0.1mol/L,c(HBr)=1.6mol/L,则H2的可能的起始浓度是()?0.1.3mol/L.3mol/L.
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![(5)某温度下,H2(g)+Br2(g)==2HBr(g),达到平衡时,c(H2)=0.5mol/L,c(Br2)=0.1mol/L,c(HBr)=1.6mol/L,则H2的可能的起始浓度是()?0.1.3mol/L.3mol/L.](/uploads/image/z/5001491-11-1.jpg?t=%EF%BC%885%EF%BC%89%E6%9F%90%E6%B8%A9%E5%BA%A6%E4%B8%8B%2CH2%28g%29%2BBr2%28g%29%3D%3D2HBr%28g%29%2C%E8%BE%BE%E5%88%B0%E5%B9%B3%E8%A1%A1%E6%97%B6%2Cc%28H2%29%3D0.5mol%2FL%2Cc%28Br2%29%3D0.1mol%2FL%2Cc%28HBr%29%3D1.6mol%2FL%2C%E5%88%99H2%E7%9A%84%E5%8F%AF%E8%83%BD%E7%9A%84%E8%B5%B7%E5%A7%8B%E6%B5%93%E5%BA%A6%E6%98%AF%EF%BC%88%EF%BC%89%3F0.1.3mol%2FL.3mol%2FL.)
(5)某温度下,H2(g)+Br2(g)==2HBr(g),达到平衡时,c(H2)=0.5mol/L,c(Br2)=0.1mol/L,c(HBr)=1.6mol/L,则H2的可能的起始浓度是()?0.1.3mol/L.3mol/L.
(5)某温度下,H2(g)+Br2(g)==2HBr(g),达到平衡时,c(H2)=0.5mol/L,c(Br2)=0.1mol/L,c(HBr)=1.6mol/L,则H2的可能的起始浓度是()?
0.1.3mol/L.3mol/L.
(5)某温度下,H2(g)+Br2(g)==2HBr(g),达到平衡时,c(H2)=0.5mol/L,c(Br2)=0.1mol/L,c(HBr)=1.6mol/L,则H2的可能的起始浓度是()?0.1.3mol/L.3mol/L.
若一开始没有HBr
要H2=0.8
所以共1.3
若一开始没有Br
氢气中有0.1来自HBr
共0.4
平衡反应考虑一开始的情况,反应可以正也可以逆