等差数列{an}的首项a1>0,前n项和为sn,且sm=sn(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大等差数列{an}的首项a1>0,前n项和为sn,且sm=sk(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大
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![等差数列{an}的首项a1>0,前n项和为sn,且sm=sn(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大等差数列{an}的首项a1>0,前n项和为sn,且sm=sk(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大](/uploads/image/z/4562663-23-3.jpg?t=%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E7%9A%84%E9%A6%96%E9%A1%B9a1%3E0%2C%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BAsn%2C%E4%B8%94sm%3Dsn%28m%2Ck%E4%B8%BA%E5%B8%B8%E6%95%B0%E4%B8%94m%E2%89%A0k%29%2C%E5%88%99%E2%91%A0s%28m%2Bk%29%3D%3F%E2%91%A1%E5%BD%93n%E4%B8%BA%E4%BD%95%E5%80%BC%EF%BC%9Asn%E5%80%BC%E6%9C%80%E5%A4%A7%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E7%9A%84%E9%A6%96%E9%A1%B9a1%3E0%2C%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B8%BAsn%2C%E4%B8%94sm%3Dsk%28m%2Ck%E4%B8%BA%E5%B8%B8%E6%95%B0%E4%B8%94m%E2%89%A0k%29%2C%E5%88%99%E2%91%A0s%28m%2Bk%29%3D%3F%E2%91%A1%E5%BD%93n%E4%B8%BA%E4%BD%95%E5%80%BC%EF%BC%9Asn%E5%80%BC%E6%9C%80%E5%A4%A7)
等差数列{an}的首项a1>0,前n项和为sn,且sm=sn(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大等差数列{an}的首项a1>0,前n项和为sn,且sm=sk(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大
等差数列{an}的首项a1>0,前n项和为sn,且sm=sn(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大
等差数列{an}的首项a1>0,前n项和为sn,且sm=sk(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大
(m+k)指下标
等差数列{an}的首项a1>0,前n项和为sn,且sm=sn(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大等差数列{an}的首项a1>0,前n项和为sn,且sm=sk(m,k为常数且m≠k),则①s(m+k)=?②当n为何值:sn值最大
数列问题可以借助函数图像来解题
sm=sk a1>0
可以判断d
K在哪里?
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