1、a²-b²+2a+1 2、(x²+3x)²-8(x²+3x)-20 因式分解
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 20:06:43
![1、a²-b²+2a+1 2、(x²+3x)²-8(x²+3x)-20 因式分解](/uploads/image/z/4488507-27-7.jpg?t=1%E3%80%81a%26%23178%3B-b%26%23178%3B%2B2a%2B1+2%E3%80%81%28x%26%23178%3B%2B3x%29%26%23178%3B-8%28x%26%23178%3B%2B3x%29-20+%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3)
1、a²-b²+2a+1 2、(x²+3x)²-8(x²+3x)-20 因式分解
1、a²-b²+2a+1 2、(x²+3x)²-8(x²+3x)-20 因式分解
1、a²-b²+2a+1 2、(x²+3x)²-8(x²+3x)-20 因式分解
1、a²-b²+2a+1
=(a²+2a+1)-b²
=(a+1)²-b²
=(a+b+1)(a-b+1)
2、(x²+3x)²-8(x²+3x)-20
=(x²+3x-10)(x²+3x+2)(把x²+3x看成一个整体再十字相乘)
=(x+5)(x-2)(x+1)(x+2)
1、a²-b²+2a+1=(a+1)^2-b^2=(a+1+b)(a+1-b)
2、(x²+3x)²-8(x²+3x)-20 =(x^2+3x-10)(x^2+3x+2)=(x^2+3x-10)(x+2)(x+1)
1.
a²-b²+2a+1
=(a²+2a+1)-b²
=(a+1)²-b²
=(a+b+1)(a-b+1)
2.
(x²+3x)²-8(x²+3x)-20
=(x²+3x-10)(x²+3x+2)
=(x+5)(x-2)(x+1)(x+2)