已知A=(a+2)(a-2),B=2(6-1/2a²),C=(a-1)²,化简3A+2B-C
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![已知A=(a+2)(a-2),B=2(6-1/2a²),C=(a-1)²,化简3A+2B-C](/uploads/image/z/445250-2-0.jpg?t=%E5%B7%B2%E7%9F%A5A%3D%28a%2B2%29%28a-2%29%2CB%3D2%286-1%2F2a%26%23178%3B%29%2CC%3D%28a-1%29%26%23178%3B%2C%E5%8C%96%E7%AE%803A%2B2B-C)
已知A=(a+2)(a-2),B=2(6-1/2a²),C=(a-1)²,化简3A+2B-C
已知A=(a+2)(a-2),B=2(6-1/2a²),C=(a-1)²,化简3A+2B-C
已知A=(a+2)(a-2),B=2(6-1/2a²),C=(a-1)²,化简3A+2B-C
解
3A+2B-C
=3(a+2)(a-2)+4(6-1/2a²)-(a-1)²
=3(a²-4)+24-2a²-(a²-2a+1)
=(3a²-2a²-a²)+2a+(-12+24-1)
=2a+11
A=a²-4
B=12-a²
C=a²-2a+1
所以原式=3a²-12+24-2a²-a²+2a-1
=2a+11
3A+2B-C
=3(a+2)(a-2)+2×2(6-1/2a²)-(a-1)²
=3a²-12+24-2a²-a²+2a-1
=2a+11
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