化简求值:已知x²-2x=2,求代数式(x-1)²+(x+3)(x-3)+(x-3)(x-1)的值
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化简求值:已知x²-2x=2,求代数式(x-1)²+(x+3)(x-3)+(x-3)(x-1)的值
化简求值:已知x²-2x=2,求代数式(x-1)²+(x+3)(x-3)+(x-3)(x-1)的值
化简求值:已知x²-2x=2,求代数式(x-1)²+(x+3)(x-3)+(x-3)(x-1)的值
(x-1)²+(x+3)(x-3)+(x-3)(x-1)
=x^2-2x+1+x^2-9+x^2-4x+3
=3x^2-6x-5
=3(x^2-2x)-5
已知x²-2x=2
带入得
=3*2-5
=1
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(x-1)²+(x+3)(x-3)+(x-3)(x-1)
=x²-2x+1+x²-9+x²-4x+3
=3x²-6x-5
=3(x²-2x)-5
把x²-2x=2代入得:
原式=6-5=1