解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 06:48:37
![解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……](/uploads/image/z/4116028-4-8.jpg?t=%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A1%2F%28x%2B4%29%2B1%2F%28x%2B7%29%3D1%2F%28x%2B5%29%2B1%2F%28x%2B6%29%E6%88%91%E6%98%AF%E8%BF%99%E6%A0%B7%E5%86%99%E7%9A%84%EF%BC%882x%2B11%EF%BC%89%2F%28x%2B7%29%28x%2B4%29%3D%282x%2B11%29%2F%28x%2B5%29%28x%2B6%29%3B%28x%2B4%29%28x%2B7%29%3D%28x%2B5%29%28x%2B6%29%3Bx2%2B11x%2B28%3Dx2%2B11x%2B30%EF%BC%9B%E6%88%91%E7%9A%84%E6%95%B0%E5%AD%A6%E6%AF%94%E8%BE%83%E7%83%82%2C%E4%BD%86%E6%98%AF%E7%84%B6%E5%90%8E%E5%B0%B1%E4%B8%8D%E7%9F%A5%E9%81%93%E6%80%8E%E4%B9%88%E7%AE%97%E4%BA%86%E2%80%A6%E2%80%A6)
解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……
解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……
解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……
:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
1/(X+4)-1/(X+5)=1/(X+6)-1/(X+7)
(X+5-X-4)/(X²+9X+20)=(X+7-X-6)/(X²+13X+42)
X²+9X+20=X²+13X+42
X=-11/2
-5.5。。。。(好吧 错了不怪我) 要过程的话 我照相找给你哈
应该这样做!
1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
两边同乘以(x+4)(x+7)(x+5)(x+6)得
(x+7)(x+5)(x+6)+(x+5)(x+6)(x+4)=(x+4)(x+7)(x+6)+(x+4)(x+7)(x+5)
(x+5)(x+6)[(x+7)+(x+4)]=(x+4)(x+7)[(x+6)+(x+5)]
(x...
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应该这样做!
1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
两边同乘以(x+4)(x+7)(x+5)(x+6)得
(x+7)(x+5)(x+6)+(x+5)(x+6)(x+4)=(x+4)(x+7)(x+6)+(x+4)(x+7)(x+5)
(x+5)(x+6)[(x+7)+(x+4)]=(x+4)(x+7)[(x+6)+(x+5)]
(x+5)(x+6)(2x+11)=(x+4)(x+7)(2x+11)
(x+5)(x+6)(2x+11)-(x+4)(x+7)(2x+11)=0
(2x+11)[(x+5)(x+6)-(x+4)(x+7)]=0
2*(2x+11)=0
所以2x+11=0
x=﹣11/2
经检验
x=﹣11/2
是原方程的解
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通分(2x+11)/(x+4)(x+7)=(2x+11)/(x+5)(x+6)(2x+11)[1/(x^2+11x+28)-1/(x^2+11x+30)]=0x^2+11x+28≠x^2+11x+30所以1/(x^2+11x+28)-1/(x^2+11x+30)≠0所以2x+11=0x=-11/2分式方程要检验经检验swaex=-11&#47...
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通分(2x+11)/(x+4)(x+7)=(2x+11)/(x+5)(x+6)(2x+11)[1/(x^2+11x+28)-1/(x^2+11x+30)]=0x^2+11x+28≠x^2+11x+30所以1/(x^2+11x+28)-1/(x^2+11x+30)≠0所以2x+11=0x=-11/2分式方程要检验经检验swaex=-11/2是方程的解
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