C语言题目:有如下定义:int x[]={1,2,3},*p=x,y;则y=*p++;相当于:A.y=*(p+1),p=p+1B.y=1,x++C.y=2,p=x+1D.y=*p,p++
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![C语言题目:有如下定义:int x[]={1,2,3},*p=x,y;则y=*p++;相当于:A.y=*(p+1),p=p+1B.y=1,x++C.y=2,p=x+1D.y=*p,p++](/uploads/image/z/3992718-30-8.jpg?t=C%E8%AF%AD%E8%A8%80%E9%A2%98%E7%9B%AE%EF%BC%9A%E6%9C%89%E5%A6%82%E4%B8%8B%E5%AE%9A%E4%B9%89%EF%BC%9Aint+x%5B%5D%3D%7B1%2C2%2C3%7D%2C%2Ap%3Dx%2Cy%3B%E5%88%99y%3D%2Ap%2B%2B%3B%E7%9B%B8%E5%BD%93%E4%BA%8E%EF%BC%9AA.y%3D%2A%28p%2B1%29%2Cp%3Dp%2B1B.y%3D1%2Cx%2B%2BC.y%3D2%2Cp%3Dx%2B1D.y%3D%2Ap%2Cp%2B%2B)
C语言题目:有如下定义:int x[]={1,2,3},*p=x,y;则y=*p++;相当于:A.y=*(p+1),p=p+1B.y=1,x++C.y=2,p=x+1D.y=*p,p++
C语言题目:有如下定义:int x[]={1,2,3},*p=x,y;则y=*p++;相当于:
A.y=*(p+1),p=p+1
B.y=1,x++
C.y=2,p=x+1
D.y=*p,p++
C语言题目:有如下定义:int x[]={1,2,3},*p=x,y;则y=*p++;相当于:A.y=*(p+1),p=p+1B.y=1,x++C.y=2,p=x+1D.y=*p,p++
应该是D,*,++优先级是一样的的,运算方式是右结合.所以先计算++(地址加1),再计算*.但++是先访问再++生效,所以取址运算还是对加1前的p.