先化简再计算x²-1/x²+x÷{x-【2x-1/x】},其中X=根号2+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/29 01:21:25
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先化简再计算x²-1/x²+x÷{x-【2x-1/x】},其中X=根号2+1
先化简再计算x²-1/x²+x÷{x-【2x-1/x】},其中X=根号2+1
先化简再计算x²-1/x²+x÷{x-【2x-1/x】},其中X=根号2+1
x=√2+1
1/x=1/(√2+1)=√2-1
x²-1/x²+x÷{x-【2x-1/x】}
=x²-1/x²+x÷(x²-2x+1)/x
=x²-1/x²+x²/(x-1)²
=(x+1/x)(x-1/x)+[x/(x-1)]²
=2√2*2+(√2+1)²/2
=4√2+3/2+√2
=5√2+3/2
(x^2-1)/(x^2+x)÷[x-(2x-1)/x]
=(x-1)(x+1)/x(x+1)÷[(x^2-2x+1)/x]
=(x-1)/x÷(x-1)^2/x
=[(x-1)/x][x/(x-1)^2]
=1/(x-1)
=1/[(√2+1)-1]
=1/√2
=√2/2
x²-1/x²是(x²-1)/x²还是 x²-(1/x²),x²是不是分子的一部分???