复合函数求导f(x)=1/(3-x)²的导数是什么?我觉得应该是1/2(3-x)³,可答案是-2(3-x)/(x²-6x﹢9)²我是用先设3-x=t,则f'(x)=t'×﹙-1/2t³﹚=1/2(3-x)³而答案是先把括号里的拆开再求
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![复合函数求导f(x)=1/(3-x)²的导数是什么?我觉得应该是1/2(3-x)³,可答案是-2(3-x)/(x²-6x﹢9)²我是用先设3-x=t,则f'(x)=t'×﹙-1/2t³﹚=1/2(3-x)³而答案是先把括号里的拆开再求](/uploads/image/z/3859398-54-8.jpg?t=%E5%A4%8D%E5%90%88%E5%87%BD%E6%95%B0%E6%B1%82%E5%AF%BCf%28x%29%3D1%2F%283%EF%BC%8Dx%29%26%23178%3B%E7%9A%84%E5%AF%BC%E6%95%B0%E6%98%AF%E4%BB%80%E4%B9%88%3F%E6%88%91%E8%A7%89%E5%BE%97%E5%BA%94%E8%AF%A5%E6%98%AF1%2F2%283%EF%BC%8Dx%29%26%23179%3B%2C%E5%8F%AF%E7%AD%94%E6%A1%88%E6%98%AF-2%283%EF%BC%8Dx%29%2F%28x%26%23178%3B%EF%BC%8D6x%EF%B9%A29%29%26%23178%3B%E6%88%91%E6%98%AF%E7%94%A8%E5%85%88%E8%AE%BE3-x%3Dt%2C%E5%88%99f%27%28x%29%3Dt%27%C3%97%EF%B9%99-1%2F2t%26%23179%3B%EF%B9%9A%3D1%2F2%283%EF%BC%8Dx%29%26%23179%3B%E8%80%8C%E7%AD%94%E6%A1%88%E6%98%AF%E5%85%88%E6%8A%8A%E6%8B%AC%E5%8F%B7%E9%87%8C%E7%9A%84%E6%8B%86%E5%BC%80%E5%86%8D%E6%B1%82)
复合函数求导f(x)=1/(3-x)²的导数是什么?我觉得应该是1/2(3-x)³,可答案是-2(3-x)/(x²-6x﹢9)²我是用先设3-x=t,则f'(x)=t'×﹙-1/2t³﹚=1/2(3-x)³而答案是先把括号里的拆开再求
复合函数求导f(x)=1/(3-x)²的导数是什么?
我觉得应该是1/2(3-x)³,可答案是-2(3-x)/(x²-6x﹢9)²
我是用先设3-x=t,
则f'(x)=t'×﹙-1/2t³﹚=1/2(3-x)³
而答案是先把括号里的拆开再求导的,
请问我哪里错了?~~~~(>_
复合函数求导f(x)=1/(3-x)²的导数是什么?我觉得应该是1/2(3-x)³,可答案是-2(3-x)/(x²-6x﹢9)²我是用先设3-x=t,则f'(x)=t'×﹙-1/2t³﹚=1/2(3-x)³而答案是先把括号里的拆开再求
f'(x)=f对t求导*t',你的f对t求导写错了,应该是-2/t³,不是-1/2t³,答案不对吧,应该没有-号
f'(x)={0-[(3-x)²]'}/[(3-x)²]²=-2(3-x)/(x²-6x﹢9)²