点E在AB上,AC=AD,∠CAB=∠DAB 求证:△ACE全等于△ADE △ACB全等于△ADB
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 21:04:09
![点E在AB上,AC=AD,∠CAB=∠DAB 求证:△ACE全等于△ADE △ACB全等于△ADB](/uploads/image/z/3843129-57-9.jpg?t=%E7%82%B9E%E5%9C%A8AB%E4%B8%8A%2CAC%3DAD%2C%E2%88%A0CAB%3D%E2%88%A0DAB+%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3ACE%E5%85%A8%E7%AD%89%E4%BA%8E%E2%96%B3ADE+%E2%96%B3ACB%E5%85%A8%E7%AD%89%E4%BA%8E%E2%96%B3ADB)
点E在AB上,AC=AD,∠CAB=∠DAB 求证:△ACE全等于△ADE △ACB全等于△ADB
点E在AB上,AC=AD,∠CAB=∠DAB 求证:△ACE全等于△ADE △ACB全等于△ADB
点E在AB上,AC=AD,∠CAB=∠DAB 求证:△ACE全等于△ADE △ACB全等于△ADB
在△ACE与△ADE中
AC=AD
∠CAB=∠DAB
AE=AE
∴△ACE≡△ADE
同理,AB为公共边,所以两三角形全等