把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 15:42:27
![把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=](/uploads/image/z/3817777-49-7.jpg?t=%E6%8A%8A%28X-Y%29%E5%92%8C%28X%2BY%29%E5%90%84%E7%9C%8B%E4%BD%9C%E4%B8%80%E4%B8%AA%E5%AD%97%E6%AF%8D%E5%9B%A0%E5%BC%8F%2C%E5%90%88%E5%B9%B6%E5%90%8C%E7%B1%BB%E9%A1%B93%EF%BC%88X%2BY%29%26%23178%3B-%EF%BC%88X-Y%29%2B2%28X%2BY%29%26%23178%3B%2B%EF%BC%88X-Y%29-5%28X%2BY%29%26%23178%3B%3D)
把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=
把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=
把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²=
3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X+Y)²
=3(X+Y)²+2(X+Y)²-5(X+Y)²-(X-Y)+(X-Y)
=0
全都抵消了,等于零