用分解因式法解方程:2(t²-1)+t=1
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用分解因式法解方程:2(t²-1)+t=1
用分解因式法解方程:2(t²-1)+t=1
用分解因式法解方程:2(t²-1)+t=1
2(t²-1)+t=1
2 (t+1) (t-1) + (t-1) =0
(t-1)(2t+3)=0
t-1=0或2t+3=0
t=1 或 t=-3/2
2(t²-1)+t=2(t-1)(t+1)+t=1 2(t-1)(t+1)=1-t -2(t+1)=1
t=-3/2 或 t=1
2(t²-1)+t=1
2t²-2+t=1
2t²-2+t-1 =0
2t²+t-3 =0
(2t+3)(t-1)=0
t=-3/2或t=1
解;2t²+t-3 =0
(2t+3)(t-1)=0
t=-2/3或t=1 。