设函数f(x)=3sin(wx+π/6),w>0,x属于R,且以π/2为最小正周期 (1)求f(0)? (2)求f(x)的解析式?(3)已知f(a/4+π/12)=9/5,求sina的值 a为α
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![设函数f(x)=3sin(wx+π/6),w>0,x属于R,且以π/2为最小正周期 (1)求f(0)? (2)求f(x)的解析式?(3)已知f(a/4+π/12)=9/5,求sina的值 a为α](/uploads/image/z/3723733-37-3.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%3D3sin%28wx%2B%CF%80%2F6%29%2Cw%3E0%2Cx%E5%B1%9E%E4%BA%8ER%2C%E4%B8%94%E4%BB%A5%CF%80%2F2%E4%B8%BA%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F+%EF%BC%881%EF%BC%89%E6%B1%82f%280%29%3F+%282%29%E6%B1%82f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%3F%EF%BC%883%EF%BC%89%E5%B7%B2%E7%9F%A5f%28a%2F4%2B%CF%80%2F12%29%3D9%2F5%2C%E6%B1%82sina%E7%9A%84%E5%80%BC+++++a%E4%B8%BA%CE%B1)
设函数f(x)=3sin(wx+π/6),w>0,x属于R,且以π/2为最小正周期 (1)求f(0)? (2)求f(x)的解析式?(3)已知f(a/4+π/12)=9/5,求sina的值 a为α
设函数f(x)=3sin(wx+π/6),w>0,x属于R,且以π/2为最小正周期 (1)求f(0)? (2)求f(x)的解析式?
(3)已知f(a/4+π/12)=9/5,求sina的值
a为α
设函数f(x)=3sin(wx+π/6),w>0,x属于R,且以π/2为最小正周期 (1)求f(0)? (2)求f(x)的解析式?(3)已知f(a/4+π/12)=9/5,求sina的值 a为α
f(0)=3sin(w0+π/6),=3sin(π/6)=3/2
,π/2为最小正周期
∴根据公式T=2π/w ∴W=4
∴f(x)=3sin(4x+π/6)
第三问
f(a/4+π/12)=9/5
∴f(a/4+π/12)=3sin(4(a/4+π/12)+π/6)=3sin(a+π/3+π/6)=3cos(a)=9/5
所以cosa=3/5
根据公式cosa的平方=sina的平方=1
得sina=1-3/5的平方=+-4/5
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