cos60°/(1+sin60°)+ 1/tan30° =1/2/(1+√3/2 )+1/√3/3 =1/( 2+√3)+√3cos60°/(1+sin60°)+ 1/tan30°=1/2/(1+√3/2 )+1/√3/3=1/( 2+√3)+√3=(4+2√3)/(2+√3)=(4+2√3)(2-√3)/(2+√3)(2-√3)=8-6=2 (1/2)/(1+√3/2 )怎么变成1/(2+√3)的,
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 05:28:27
![cos60°/(1+sin60°)+ 1/tan30° =1/2/(1+√3/2 )+1/√3/3 =1/( 2+√3)+√3cos60°/(1+sin60°)+ 1/tan30°=1/2/(1+√3/2 )+1/√3/3=1/( 2+√3)+√3=(4+2√3)/(2+√3)=(4+2√3)(2-√3)/(2+√3)(2-√3)=8-6=2 (1/2)/(1+√3/2 )怎么变成1/(2+√3)的,](/uploads/image/z/3709717-61-7.jpg?t=cos60%C2%B0%2F%281%2Bsin60%C2%B0%29%2B+1%2Ftan30%C2%B0+%3D1%2F2%2F%281%2B%E2%88%9A3%2F2+%29%2B1%2F%E2%88%9A3%2F3+%3D1%2F%28+2%2B%E2%88%9A3%29%2B%E2%88%9A3cos60%C2%B0%2F%281%2Bsin60%C2%B0%29%2B+1%2Ftan30%C2%B0%3D1%2F2%2F%281%2B%E2%88%9A3%2F2+%29%2B1%2F%E2%88%9A3%2F3%3D1%2F%28+2%2B%E2%88%9A3%29%2B%E2%88%9A3%3D%284%2B2%E2%88%9A3%29%2F%282%2B%E2%88%9A3%29%3D%284%2B2%E2%88%9A3%29%282-%E2%88%9A3%29%2F%282%2B%E2%88%9A3%29%282-%E2%88%9A3%29%3D8-6%3D2+%281%2F2%29%2F%281%2B%E2%88%9A3%2F2+%29%E6%80%8E%E4%B9%88%E5%8F%98%E6%88%901%2F%282%2B%E2%88%9A3%29%E7%9A%84%2C)
cos60°/(1+sin60°)+ 1/tan30° =1/2/(1+√3/2 )+1/√3/3 =1/( 2+√3)+√3cos60°/(1+sin60°)+ 1/tan30°=1/2/(1+√3/2 )+1/√3/3=1/( 2+√3)+√3=(4+2√3)/(2+√3)=(4+2√3)(2-√3)/(2+√3)(2-√3)=8-6=2 (1/2)/(1+√3/2 )怎么变成1/(2+√3)的,
cos60°/(1+sin60°)+ 1/tan30° =1/2/(1+√3/2 )+1/√3/3 =1/( 2+√3)+√3
cos60°/(1+sin60°)+ 1/tan30°
=1/2/(1+√3/2 )+1/√3/3
=1/( 2+√3)+√3
=(4+2√3)/(2+√3)
=(4+2√3)(2-√3)/(2+√3)(2-√3)
=8-6
=2
(1/2)/(1+√3/2 )怎么变成1/(2+√3)的,还有1/(√3/3 )怎么变√3的?
cos60°/(1+sin60°)+ 1/tan30° =1/2/(1+√3/2 )+1/√3/3 =1/( 2+√3)+√3cos60°/(1+sin60°)+ 1/tan30°=1/2/(1+√3/2 )+1/√3/3=1/( 2+√3)+√3=(4+2√3)/(2+√3)=(4+2√3)(2-√3)/(2+√3)(2-√3)=8-6=2 (1/2)/(1+√3/2 )怎么变成1/(2+√3)的,
第一个是分子和分母都同时乘以了2;第二个是分子和分母都同乘以3.
第一个分子分母同乘以2,第二个分子分母同乘以3,就变成了√3/3,又因为(√3)2=3,所以√3/3=√3
59千克,因为题目中说的是从第一筐中取出2分之1千克,不是说从第一筐中取出它的2分之1,所以不是取了15千克
设第二筐重X千克。
30-1/2=X+1/2
X=29
30+29=59(千克)
答:两筐共重59千克