已知f(x)=2sin(2x+π/6) 且过点(0,1)(11π/12,0)设0
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已知f(x)=2sin(2x+π/6) 且过点(0,1)(11π/12,0)设0
已知f(x)=2sin(2x+π/6) 且过点(0,1)(11π/12,0)设0
已知f(x)=2sin(2x+π/6) 且过点(0,1)(11π/12,0)设0
解析:
因为0
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