若ab≠1且有5a²+2001a+9及9b²+2001b+5=0,则a/b的值为?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 18:35:48
![若ab≠1且有5a²+2001a+9及9b²+2001b+5=0,则a/b的值为?](/uploads/image/z/3676412-20-2.jpg?t=%E8%8B%A5ab%E2%89%A01%E4%B8%94%E6%9C%895a%26%23178%3B%2B2001a%2B9%E5%8F%8A9b%26%23178%3B%2B2001b%2B5%3D0%2C%E5%88%99a%2Fb%E7%9A%84%E5%80%BC%E4%B8%BA%3F)
若ab≠1且有5a²+2001a+9及9b²+2001b+5=0,则a/b的值为?
若ab≠1且有5a²+2001a+9及9b²+2001b+5=0,则a/b的值为?
若ab≠1且有5a²+2001a+9及9b²+2001b+5=0,则a/b的值为?
9b²+2001b+5=0
两边除以b²
5(1/b)²+2001(1/b)+9=0
5a²+2001a+9=0
所以a和1/b是5x²+2001x+9=0的解
则x1x2=9/5
所以a/b=9/5