a=2-√2,b=2+√2求(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²
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a=2-√2,b=2+√2求(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²
a=2-√2,b=2+√2求(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²
a=2-√2,b=2+√2求(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²
(a³b+a²b²分之a²+2ab+b²)÷(a²-ab分之a²-b²)
=【a²b(a+b)分之(a+b)²】/【a(a-b)分之((a+b)(a-b))】
=a²b分之(a+b)*(a+b)分之a
=1/(ab)
=1/【(2-√2)*(2+√2)】
=1/【2²-2】
=1/2
原式=[(a+b)^2/a^2b(a+b)]÷(a+b)(a-b)/a(a-b)
=(a+b)/a^2b÷(a+b)/a
=(a+b)/a^2b*a/(a+b)
=1/(ab)
代入数值,得
1/(2-√2)(2+√2)=1/(4-2)=1/2