(2ab²/a+b)÷(ab³/a²-b²)²x 【1/ 2(a-b)】² 化简
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![(2ab²/a+b)÷(ab³/a²-b²)²x 【1/ 2(a-b)】² 化简](/uploads/image/z/3654407-47-7.jpg?t=%282ab%26%23178%3B%2Fa%2Bb%29%C3%B7%EF%BC%88ab%26%23179%3B%2Fa%26%23178%3B-b%26%23178%3B%EF%BC%89%26%23178%3Bx+%E3%80%901%2F+2%EF%BC%88a-b%EF%BC%89%E3%80%91%26%23178%3B+%E5%8C%96%E7%AE%80)
(2ab²/a+b)÷(ab³/a²-b²)²x 【1/ 2(a-b)】² 化简
(2ab²/a+b)÷(ab³/a²-b²)²x 【1/ 2(a-b)】² 化简
(2ab²/a+b)÷(ab³/a²-b²)²x 【1/ 2(a-b)】² 化简
(2ab²/a+b)÷(ab³/a²-b²)²x 【1/ 2(a-b)】²
=2ab²/(a+b)÷(a²b^6/(a+b)²(a-b)²)x 1/ 4(a-b)²
=(a+b)/2ab^4
如追加其它问题,采纳本题后点击想我求助,
原式=(2ab²/a+b) x [(a+b)²(a-b)²/(a²b³)²] x [1/ 2(a-b)]² (对各个分式进行约分)
=(a+b)/2ab^4