应用(a+b)(a-b)=a²-b²的公式计算(x+2y-1)(x-2y+1)
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应用(a+b)(a-b)=a²-b²的公式计算(x+2y-1)(x-2y+1)
应用(a+b)(a-b)=a²-b²的公式计算(x+2y-1)(x-2y+1)
应用(a+b)(a-b)=a²-b²的公式计算(x+2y-1)(x-2y+1)
(x+2y-1)(x-2y+1)=[x+(2y-1)][(x-(2y-1)]=x^2-(2y-1)^2=x^2-4y^2+4y-1
原式=x^2-(2y-1)^2
=x^2-(4y^2-4y+1)
=x^2-4y^2+4y-1
x²—(1—2y)²