lim x→0 (x-sinx)/(x-tanx) 请问怎么用洛必达法则求极限?请告诉我怎么用洛必达法则求这道题,望详解,
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![lim x→0 (x-sinx)/(x-tanx) 请问怎么用洛必达法则求极限?请告诉我怎么用洛必达法则求这道题,望详解,](/uploads/image/z/350501-5-1.jpg?t=lim+x%E2%86%920+%28x-sinx%29%2F%28x-tanx%29+%E8%AF%B7%E9%97%AE%E6%80%8E%E4%B9%88%E7%94%A8%E6%B4%9B%E5%BF%85%E8%BE%BE%E6%B3%95%E5%88%99%E6%B1%82%E6%9E%81%E9%99%90%3F%E8%AF%B7%E5%91%8A%E8%AF%89%E6%88%91%E6%80%8E%E4%B9%88%E7%94%A8%E6%B4%9B%E5%BF%85%E8%BE%BE%E6%B3%95%E5%88%99%E6%B1%82%E8%BF%99%E9%81%93%E9%A2%98%2C%E6%9C%9B%E8%AF%A6%E8%A7%A3%2C)
lim x→0 (x-sinx)/(x-tanx) 请问怎么用洛必达法则求极限?请告诉我怎么用洛必达法则求这道题,望详解,
lim x→0 (x-sinx)/(x-tanx) 请问怎么用洛必达法则求极限?
请告诉我怎么用洛必达法则求这道题,望详解,
lim x→0 (x-sinx)/(x-tanx) 请问怎么用洛必达法则求极限?请告诉我怎么用洛必达法则求这道题,望详解,
连续使用L'Hospital Rule
lim x→0 (x-sinx)/(x-tanx)
=lim x→0 (1-cosx)/(1-(secx)^2)
=lim x→0 (sinx)/(-2secx·secx·tanx)
=lim x→0 -(cosx)^3/2
=-1/2
lim (x→0)x-sinx/x
lim(x→0)sinx/|x|rt
lim x-sinx/x+sinxx→0
lim x→0 x/sinx=
lim(x→0)arctan(sinx/x)
lim x→0((x+ sinx)/tanx)
lim x→0(sinx)^x
lim(x→0)(x-sinx)/(x+sinx)
lim(x→0) x-sinx/x+sinx的极限
lim[(x-sinx)/(x+sinx)] x→0
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lim (x->0) 3x/(sinx-x)
求极限lim(x→0)x-sinx/x^3
lim(x→0)[e^x-e^(-x)]/sinx=?
lim(x→0) sinx-x(x+1)/xsinx
lim (x→0) (e^x-x)^(1/sinx)
当x→0时,lim (x-sinx)/x=?