﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 11:36:31
![﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2](/uploads/image/z/342738-18-8.jpg?t=%EF%B9%993a%26%23179%3B-5%26%23178%3B%EF%B9%9A%C3%B7%EF%B9%99-3%E5%88%86%E4%B9%8B1a%26%23178%3B%EF%B9%9A-%EF%B9%996a%26%23178%3B-4a%EF%B9%9A%C3%B72)
﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
题目应是 ﹙3a³-a²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
=-9a+3-3a²+2a
=-3a²-7a+3
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 11:36:31
﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
﹙3a³-5²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
题目应是 ﹙3a³-a²﹚÷﹙-3分之1a²﹚-﹙6a²-4a﹚÷2
=-9a+3-3a²+2a
=-3a²-7a+3