如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),
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![如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),](/uploads/image/z/319127-23-7.jpg?t=%E5%A6%82%E6%9E%9Cx%2F2%3Dy%2F3%3Dz%2F5%2C%E4%B8%94xyz%E4%B8%8D%E7%AD%89%E4%BA%8E0%2C%E5%88%99%28x%2By%2Bz%29%2F%EF%BC%883x-y%EF%BC%89%2C)
如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),
如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),
如果x/2=y/3=z/5,且xyz不等于0,则(x+y+z)/(3x-y),
x/2=y/3=z/5
所以y=3x/2
z=5x/2
(x+y+z)/(3x-y)
=(x+3x/2+5x/2)/(3x-3x/2)
=5x/(3x/2)
=5/(3/2)
=10/3