1若x+2y=0 ,xy不等于0,求分式 x^2+2xy / xy+y^2
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![1若x+2y=0 ,xy不等于0,求分式 x^2+2xy / xy+y^2](/uploads/image/z/3044654-62-4.jpg?t=1%E8%8B%A5x%2B2y%3D0+%2Cxy%E4%B8%8D%E7%AD%89%E4%BA%8E0%2C%E6%B1%82%E5%88%86%E5%BC%8F+x%5E2%2B2xy+%2F+xy%2By%5E2)
1若x+2y=0 ,xy不等于0,求分式 x^2+2xy / xy+y^2
1
若x+2y=0 ,xy不等于0,求分式 x^2+2xy / xy+y^2
1若x+2y=0 ,xy不等于0,求分式 x^2+2xy / xy+y^2
因为x+2y=0,所以x=-2y
原式=(x^2+2xy)/(xy+y^2)=(4y^2-4Y^2)/(-3y^2+y^2)
=0/(-2y^2)
又因为xy不等于零,所以x、y君不等于零,所以-2y^2亦不等于零
所以原式=0
x^2+2xy / xy+y^2
=x(x+2y)/(xy+y^2)
=0