(1)(a²-ab)÷(ab分之b-a ) (2)(x²-1分之x+3)÷(x²-2x+1分之(x+3)(x-1))
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 04:58:51
![(1)(a²-ab)÷(ab分之b-a ) (2)(x²-1分之x+3)÷(x²-2x+1分之(x+3)(x-1))](/uploads/image/z/3011171-59-1.jpg?t=%EF%BC%881%EF%BC%89%EF%BC%88a%26%23178%3B-ab%29%C3%B7%EF%BC%88ab%E5%88%86%E4%B9%8Bb-a+%EF%BC%89+%EF%BC%882%EF%BC%89%EF%BC%88x%26%23178%3B-1%E5%88%86%E4%B9%8Bx%2B3%EF%BC%89%C3%B7%EF%BC%88x%26%23178%3B-2x%2B1%E5%88%86%E4%B9%8B%EF%BC%88x%2B3%29%28x-1%29%29)
(1)(a²-ab)÷(ab分之b-a ) (2)(x²-1分之x+3)÷(x²-2x+1分之(x+3)(x-1))
(1)(a²-ab)÷(ab分之b-a ) (2)(x²-1分之x+3)÷(x²-2x+1分之(x+3)(x-1))
(1)(a²-ab)÷(ab分之b-a ) (2)(x²-1分之x+3)÷(x²-2x+1分之(x+3)(x-1))
1)=a(a-b)x(b-a分之ab) 2)= (x+1)(x-1)分之x+3乘以 (x+3)(x-1)分之(x-1) ²
=a(a-b)x(-a-b分之ab) =x+1分之1乘以x-1分之x-1
=ax(-ab) =x+1分之1乘以1
=-a²b =x+1分之1
应该对的……看我打这么辛苦给个辛苦分吧
1. -(a^2)b
2. 1/(x+1)
1、原式=a(a-b)÷(b-a/ab)=-(a-b)²/b
2、原式=(x+3)/(x-1)(x+1)·(x-1)²/(x+3)(x-1)=1/(x+1)