若f(3)=2,f'(3)=-2,则lim(x→3) 2x-3f(x)/x-3=
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![若f(3)=2,f'(3)=-2,则lim(x→3) 2x-3f(x)/x-3=](/uploads/image/z/2688919-7-9.jpg?t=%E8%8B%A5f%283%29%3D2%2Cf%27%283%29%3D-2%2C%E5%88%99lim%28x%E2%86%923%29+2x-3f%28x%29%2Fx-3%3D)
若f(3)=2,f'(3)=-2,则lim(x→3) 2x-3f(x)/x-3=
若f(3)=2,f'(3)=-2,则lim(x→3) 2x-3f(x)/x-3=
若f(3)=2,f'(3)=-2,则lim(x→3) 2x-3f(x)/x-3=
f'(3)=-2=lim(x→3)(f(x)-f(3))/(x-3)=lim(x→3)(f(x)-2)/(x-3)
lim(x→3) 2x-3f(x)/x-3=lim(x→3)(2x-6+6-3f(x))/(x-3)
=lim(x→3)(2-3(f(x)-2)/(x-3))=2-3*(-2)=8