[(1/m)-(1/n)]/[(m²-2mn+n²)/mn]
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![[(1/m)-(1/n)]/[(m²-2mn+n²)/mn]](/uploads/image/z/2586978-18-8.jpg?t=%5B%EF%BC%881%2Fm%29-%281%2Fn%29%5D%2F%5B%28m%26%23178%3B-2mn%2Bn%26%23178%3B%29%2Fmn%5D)
[(1/m)-(1/n)]/[(m²-2mn+n²)/mn]
[(1/m)-(1/n)]/[(m²-2mn+n²)/mn]
[(1/m)-(1/n)]/[(m²-2mn+n²)/mn]
原式=(n-m)/(mn)÷[(m-n)²/(mn)]
=(n-m)/(mn)×(mn)/(m-n)²;
=1/(n-m);
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