求极限 lim (1+2+3+...+n/n+2-n/2)趋向是正无穷lim (1+2+3+...+n/(n+2)-n/2)趋向是正无穷
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 02:46:29
![求极限 lim (1+2+3+...+n/n+2-n/2)趋向是正无穷lim (1+2+3+...+n/(n+2)-n/2)趋向是正无穷](/uploads/image/z/2576859-51-9.jpg?t=%E6%B1%82%E6%9E%81%E9%99%90+lim+%281%2B2%2B3%2B...%2Bn%2Fn%2B2-n%2F2%29%E8%B6%8B%E5%90%91%E6%98%AF%E6%AD%A3%E6%97%A0%E7%A9%B7lim+%281%2B2%2B3%2B...%2Bn%2F%28n%2B2%29-n%2F2%29%E8%B6%8B%E5%90%91%E6%98%AF%E6%AD%A3%E6%97%A0%E7%A9%B7)
求极限 lim (1+2+3+...+n/n+2-n/2)趋向是正无穷lim (1+2+3+...+n/(n+2)-n/2)趋向是正无穷
求极限 lim (1+2+3+...+n/n+2-n/2)趋向是正无穷
lim (1+2+3+...+n/(n+2)-n/2)趋向是正无穷
求极限 lim (1+2+3+...+n/n+2-n/2)趋向是正无穷lim (1+2+3+...+n/(n+2)-n/2)趋向是正无穷
-1/2
如果题目没有错的话,还是正无穷,不过我认为你的题目有问题,分母怎么是
n+2-n/2直接是n/2+2不就行了?
怀念阿,你是高中生吧。不知道你题目有没有打错阿。 分子用求和公式,再同时乘2,再分子分母同时除n,得到,(n+1)/(1+4/n) ,4根据极限运算法则,4/n的极限是0,故所求极限为n+1,故趋向正无穷.......hehe
求极限lim 2/(3^n-1)
求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞)
lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限
求极限lim(x→∞)(1/n+2/n+3/n..+n/n)
求极限lim(n+1/n+3)^n如题
求极限n~∞,lim(n+1)/2n
求极限Lim((n-x)/(n+2))^(n+1)
lim (1+2/n)^n+4 n-->无穷大 求极限
求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞)
求极限lim (3^n+1-2^n+1)/(3^n+2^n)
求极限:lim((2n∧2-3n+1)/n+1)×sin n趋于无穷
求极限lim(n→∞)(3n^2-n+1)/(2+n^2)?
求lim(n->无穷)(3n+5)/(n^2+n+4)^1/2的极限
求极限:lim{1+[1/(2n-1)]}^n
高数 数列极限lim(1+ 2^n + 3^n)^(1/n) n趋于无穷大求极限
1.6求极限lim(x→∞) [1+2+3+......+(n-1)]/ n^21.6求极限lim(x→∞) [1+2+3+......+(n-1)]/ n^2
求极限 x→∞lim(3^n+1)/(3^(n+1)+2^n)=
求极限lim[n→∞](n^2+1)/(2n^2+3)