请问lim(x→0){(1-cosx)/[(e^x-1)ln(1+x)]}=?不太懂等价的知识。不知有没有化简的方法?
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![请问lim(x→0){(1-cosx)/[(e^x-1)ln(1+x)]}=?不太懂等价的知识。不知有没有化简的方法?](/uploads/image/z/2556067-67-7.jpg?t=%E8%AF%B7%E9%97%AElim%28x%E2%86%920%29%7B%281-cosx%29%2F%5B%28e%5Ex-1%29ln%281%2Bx%29%5D%7D%3D%3F%E4%B8%8D%E5%A4%AA%E6%87%82%E7%AD%89%E4%BB%B7%E7%9A%84%E7%9F%A5%E8%AF%86%E3%80%82%E4%B8%8D%E7%9F%A5%E6%9C%89%E6%B2%A1%E6%9C%89%E5%8C%96%E7%AE%80%E7%9A%84%E6%96%B9%E6%B3%95%EF%BC%9F)
请问lim(x→0){(1-cosx)/[(e^x-1)ln(1+x)]}=?不太懂等价的知识。不知有没有化简的方法?
请问lim(x→0){(1-cosx)/[(e^x-1)ln(1+x)]}=?
不太懂等价的知识。不知有没有化简的方法?
请问lim(x→0){(1-cosx)/[(e^x-1)ln(1+x)]}=?不太懂等价的知识。不知有没有化简的方法?
1-cosx->x^2/2
e^x-1->x
ln(1+x)->x
lim(x->0)){(1-cosx)/[(e^x-1)ln(1+x)]}
=x^2/2/x^2
=1/2
0
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