(4x^2-y^2)/(x^2-4y^2)-(2x-y)^2/(x^2-4y^2)-(2y^2-4xy)/(x^2-4y^2)=?如题 、、、
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![(4x^2-y^2)/(x^2-4y^2)-(2x-y)^2/(x^2-4y^2)-(2y^2-4xy)/(x^2-4y^2)=?如题 、、、](/uploads/image/z/2541704-32-4.jpg?t=%284x%5E2-y%5E2%29%2F%28x%5E2-4y%5E2%29-%282x-y%29%5E2%2F%28x%5E2-4y%5E2%29-%282y%5E2-4xy%29%2F%28x%5E2-4y%5E2%29%3D%3F%E5%A6%82%E9%A2%98+%E3%80%81%E3%80%81%E3%80%81)
(4x^2-y^2)/(x^2-4y^2)-(2x-y)^2/(x^2-4y^2)-(2y^2-4xy)/(x^2-4y^2)=?如题 、、、
(4x^2-y^2)/(x^2-4y^2)-(2x-y)^2/(x^2-4y^2)-(2y^2-4xy)/(x^2-4y^2)=?
如题 、、、
(4x^2-y^2)/(x^2-4y^2)-(2x-y)^2/(x^2-4y^2)-(2y^2-4xy)/(x^2-4y^2)=?如题 、、、
先提公因式,再化简
原式=(2x-y)(2x+y-2x+y+2y)/(x^2-4y^2)
=(2x-y)*4y/(x^2-4y^2)=(8xy-4y^2)/(x^2-4y^2)