分解因式(x²+2x)²+2x²+4x+1还有一题ab(x²+1)+(a²+b²)要有解答过程谢谢
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 22:16:35
![分解因式(x²+2x)²+2x²+4x+1还有一题ab(x²+1)+(a²+b²)要有解答过程谢谢](/uploads/image/z/2469723-51-3.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%28x%26%23178%3B%2B2x%29%26%23178%3B%2B2x%26%23178%3B%2B4x%2B1%E8%BF%98%E6%9C%89%E4%B8%80%E9%A2%98ab%28x%26%23178%3B%2B1%29%2B%EF%BC%88a%26%23178%3B%2Bb%26%23178%3B%29%E8%A6%81%E6%9C%89%E8%A7%A3%E7%AD%94%E8%BF%87%E7%A8%8B%E8%B0%A2%E8%B0%A2)
分解因式(x²+2x)²+2x²+4x+1还有一题ab(x²+1)+(a²+b²)要有解答过程谢谢
分解因式(x²+2x)²+2x²+4x+1
还有一题ab(x²+1)+(a²+b²)要有解答过程谢谢
分解因式(x²+2x)²+2x²+4x+1还有一题ab(x²+1)+(a²+b²)要有解答过程谢谢
(x²+2x)²+2x²+4x+1
=(x²+2x)²+2(x²+2x)+1
=(x²+2x+1)²
=(x+1)
ab(x²+1)+x(a²+b²)吧,
=abx²+ab+x(a²+b²)
=abx²+x(a²+b²)+ab
=(ax+b)(bx+a)
(x²+2x)²+2x²+4x+1
=(x²+2x)²+2(x²+2x)+1
=(x²+2x+1)²
=(x+1)^4
第二题应该是ab(x²+1)+x(a²+b²)吧,
=abx²+ab+x(a²+b²)
=abx²+x(a²+b²)+ab
=(ax+b)(bx+a)十字交叉法
分解因式(x²+2x)²+2x²+4x+1=(x²+2x)²+2(x²+2x)+1=(x²+2x+1)²=(x+1)^4