计算:a²-5a+6/a²-16÷[(a-3/a+4)·(a²-4/a²+5a+4)]
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 10:39:53
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计算:a²-5a+6/a²-16÷[(a-3/a+4)·(a²-4/a²+5a+4)]
计算:a²-5a+6/a²-16÷[(a-3/a+4)·(a²-4/a²+5a+4)]
计算:a²-5a+6/a²-16÷[(a-3/a+4)·(a²-4/a²+5a+4)]
(a²-5a+6)/(a²-16)÷[(a-3)/(a+4)·(a²-4)/(a²+5a+4)]
=(a²-5a+6)/(a²-16)÷[(a-3)(a²-4)/(a+4)(a²+5a+4)]
=(a²-5a+6)/(a²-16)*(a+4)(a²+5a+4)/(a-3)(a²-4)
=(a-2)(a-3)/(a-4)(a+4)*(a+4)(a²+5a+4)/(a-3)(a²-4)
=(a-2)/(a-4)*(a²+5a+4)/(a²-4)
=(a-2)/(a-4)*(a+1)(a+4)/(a-2)(a+2)
=1/(a-4)*(a+1)(a+4)/(a+2)
=(a+1)(a+4)/(a-4)(a+2)
=(a²+5a+4)/(a²-2a-8)
a²-5a+6/a²-16÷[(a-3/a+4)·(a²-4/a²+5a+4)]
(a-2)(a-3)/(a-4)(a+4) * (a+4)/(a-3) * (a+4)(a+1)/(a-2)(a+2)
=[(a+4)(a+1)]/[(a-4)(a+2) ]