f(x)=√3sin2x-2sin²x① =√3sin2x+cos2x-1② =2sin(2x+π/6)-1③从①到②是怎么来的?
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![f(x)=√3sin2x-2sin²x① =√3sin2x+cos2x-1② =2sin(2x+π/6)-1③从①到②是怎么来的?](/uploads/image/z/1989160-16-0.jpg?t=f%28x%29%3D%E2%88%9A3sin2x%EF%BC%8D2sin%26%23178%3Bx%E2%91%A0+%3D%E2%88%9A3sin2x%EF%BC%8Bcos2x%EF%BC%8D1%E2%91%A1+%3D2sin%282x%EF%BC%8B%CF%80%2F6%29%EF%BC%8D1%E2%91%A2%E4%BB%8E%E2%91%A0%E5%88%B0%E2%91%A1%E6%98%AF%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%3F)
f(x)=√3sin2x-2sin²x① =√3sin2x+cos2x-1② =2sin(2x+π/6)-1③从①到②是怎么来的?
f(x)=√3sin2x-2sin²x① =√3sin2x+cos2x-1② =2sin(2x+π/6)-1③
从①到②是怎么来的?
f(x)=√3sin2x-2sin²x① =√3sin2x+cos2x-1② =2sin(2x+π/6)-1③从①到②是怎么来的?
sinX的平方=(1-cos2X)/2,是一个推导公式