1.-1/4(xy+1)^2+1/16(1-xy)^22.已知xy=2,x^2+y^2=5求:(x-y)^2的值.3.The weather in Kunming is nice.The weather in Guangzhou is nice,too.(合并成一句)The weather in Kunming is ( ) nice ( ) that in Guangzhou.第一题是分解因式(完整
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![1.-1/4(xy+1)^2+1/16(1-xy)^22.已知xy=2,x^2+y^2=5求:(x-y)^2的值.3.The weather in Kunming is nice.The weather in Guangzhou is nice,too.(合并成一句)The weather in Kunming is ( ) nice ( ) that in Guangzhou.第一题是分解因式(完整](/uploads/image/z/1889079-15-9.jpg?t=1.-1%2F4%28xy%2B1%29%5E2%2B1%2F16%281-xy%29%5E22.%E5%B7%B2%E7%9F%A5xy%3D2%2Cx%5E2%2By%5E2%3D5%E6%B1%82%EF%BC%9A%EF%BC%88x-y%EF%BC%89%5E2%E7%9A%84%E5%80%BC.3.The+weather+in+Kunming+is+nice.The+weather+in+Guangzhou+is+nice%2Ctoo.%28%E5%90%88%E5%B9%B6%E6%88%90%E4%B8%80%E5%8F%A5%29The+weather+in+Kunming+is+%28+%29+nice+%28+%29+that+in+Guangzhou.%E7%AC%AC%E4%B8%80%E9%A2%98%E6%98%AF%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%88%E5%AE%8C%E6%95%B4)
1.-1/4(xy+1)^2+1/16(1-xy)^22.已知xy=2,x^2+y^2=5求:(x-y)^2的值.3.The weather in Kunming is nice.The weather in Guangzhou is nice,too.(合并成一句)The weather in Kunming is ( ) nice ( ) that in Guangzhou.第一题是分解因式(完整
1.-1/4(xy+1)^2+1/16(1-xy)^2
2.已知xy=2,x^2+y^2=5
求:(x-y)^2的值.
3.The weather in Kunming is nice.The weather in Guangzhou is nice,too.(合并成一句)
The weather in Kunming is ( ) nice ( ) that in Guangzhou.
第一题是分解因式(完整过程)
1.-1/4(xy+1)^2+1/16(1-xy)^22.已知xy=2,x^2+y^2=5求:(x-y)^2的值.3.The weather in Kunming is nice.The weather in Guangzhou is nice,too.(合并成一句)The weather in Kunming is ( ) nice ( ) that in Guangzhou.第一题是分解因式(完整
第1题,-1/16(xy+3)(3xy+1)
不是吧这都要过程,就是全部去掉括号后合并同类项,得-3/16X^2*Y^2-5/8XY-3/16
-1/16(3X^2*Y^2+10XY+3)
十字相乘,得答案
第2,(X-Y)^2=X^2+Y^2-2XY=5-4=1
第3,两个空都是AS