函数y=(2-x)/(3x+6)的递减区间是?函数y=√{(2-x)/(3x+6)}即根号下(2-x)/(3x+6)的递减区间是?
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![函数y=(2-x)/(3x+6)的递减区间是?函数y=√{(2-x)/(3x+6)}即根号下(2-x)/(3x+6)的递减区间是?](/uploads/image/z/1791205-61-5.jpg?t=%E5%87%BD%E6%95%B0y%3D%282-x%29%2F%283x%2B6%29%E7%9A%84%E9%80%92%E5%87%8F%E5%8C%BA%E9%97%B4%E6%98%AF%3F%E5%87%BD%E6%95%B0y%3D%E2%88%9A%7B%282-x%29%2F%283x%2B6%29%7D%E5%8D%B3%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%882-x%29%2F%283x%2B6%29%E7%9A%84%E9%80%92%E5%87%8F%E5%8C%BA%E9%97%B4%E6%98%AF%3F)
函数y=(2-x)/(3x+6)的递减区间是?函数y=√{(2-x)/(3x+6)}即根号下(2-x)/(3x+6)的递减区间是?
函数y=(2-x)/(3x+6)的递减区间是?函数y=√{(2-x)/(3x+6)}即根号下(2-x)/(3x+6)的递减区间是?
函数y=(2-x)/(3x+6)的递减区间是?函数y=√{(2-x)/(3x+6)}即根号下(2-x)/(3x+6)的递减区间是?
1.y=(2-x)/(3x+6)
=[(-x-2)+4]/(3x+6)
=-1/3+4/[3(x+2)]
因为
y1= 4/[3(x+2)]
在
(-∞,-2),(-2,+∞)上是减函数,
所以y=(2-x)/(3x+6)的递减区间是:(-∞,-2)和(-2,+∞).
2.y=根号下(2-x)/(3x+6)
(2-x)/(3x+6)>=0
(x+2)(x-2)<=0
-2<=x<=2
但分母不为0,所以定义域为 -2