设角A,B都是钝角,tanA=(根号3)*(1+m),tan(-B)=(根号3)*(tanAtanB+m),则A+B=?
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![设角A,B都是钝角,tanA=(根号3)*(1+m),tan(-B)=(根号3)*(tanAtanB+m),则A+B=?](/uploads/image/z/1684610-26-0.jpg?t=%E8%AE%BE%E8%A7%92A%2CB%E9%83%BD%E6%98%AF%E9%92%9D%E8%A7%92%2CtanA%3D%EF%BC%88%E6%A0%B9%E5%8F%B73%EF%BC%89%2A%281%2Bm%29%2Ctan%28-B%29%3D%EF%BC%88%E6%A0%B9%E5%8F%B73%EF%BC%89%2A%28tanAtanB%2Bm%29%2C%E5%88%99A%2BB%3D%3F)
设角A,B都是钝角,tanA=(根号3)*(1+m),tan(-B)=(根号3)*(tanAtanB+m),则A+B=?
设角A,B都是钝角,tanA=(根号3)*(1+m),tan(-B)=(根号3)*(tanAtanB+m),则A+B=?
设角A,B都是钝角,tanA=(根号3)*(1+m),tan(-B)=(根号3)*(tanAtanB+m),则A+B=?
tanB=-tan(-B)
tan(A+B)=(tanA+tanB)/(1-tanAtanB)代入得
tan(A+B)=根号3
因为A,B都是钝角,所以180<A+B<360
A+B=240