怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 00:39:04
![怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²](/uploads/image/z/1653581-29-1.jpg?t=%E6%80%8E%E4%B9%88%E6%8A%8Ax%26%23178%3B-xy%2By%26%23178%3B%E5%88%86%E4%B9%8Bx%26%23178%3B%2B2xy-3y%26%23179%3B%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E5%95%8A%2C%E5%BA%94%E8%AF%A5%E6%98%AFx%26%23178%3B-xy%2By%26%23178%3B%E5%88%86%E4%B9%8Bx%26%23178%3B%2B2xy-3y%26%23178%3B)
怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²
怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,
应该是x²-xy+y²分之x²+2xy-3y²
怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,应该是x²-xy+y²分之x²+2xy-3y²
再改一下吧
x²- 2 xy+y²分之x²+2xy-3y²
=(x+3y)(x-y)/(x-y)²
=(x+3y)/(x-y)
你确定题打对了?