(x-1)(x²+x-1)-3=x(x+1)(x-1)-x²怎么解
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(x-1)(x²+x-1)-3=x(x+1)(x-1)-x²怎么解
(x-1)(x²+x-1)-3=x(x+1)(x-1)-x²怎么解
(x-1)(x²+x-1)-3=x(x+1)(x-1)-x²怎么解
(x-1)(x²+x-1)-3=x(x+1)(x-1)-x²
(x-1)(x²+x-1)-3-x(x+1)(x-1)+x²=0
(x-1)(x²+x-1-x²-x)+x²-3=0
(x-1)(-1)+x²-3=0
-x+1+x²-3=0
x²-x-2=0
(x+1)(x-2)=0
解得x=-1或x=2
(x-1)(x²+x-1)-3=x(x+1)(x-1)-x²
移项得:(x-1)(x²+x-1)-3-x(x+1)(x-1)+x²=0
提取公因式:(x-1)(x²+x-1-x(x+1))+x²-3=0
化简: - (x-1)+x²-3=0
x²-x-2=0
(x+1)(x-2)=0
解得x=-1或x=2