已知x²+y²+z²+4x+4y+4z+1=0,求x+y+1是求x+y+z的值
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已知x²+y²+z²+4x+4y+4z+1=0,求x+y+1是求x+y+z的值
已知x²+y²+z²+4x+4y+4z+1=0,求x+y+1
是求x+y+z的值
已知x²+y²+z²+4x+4y+4z+1=0,求x+y+1是求x+y+z的值
x²+4x+4+y²+4y+4+z²+4z+4=-1+4+4+4
(x+2)²+(y+2)²+(z+2)²=11
[(2-(-x))²+(2-(-y))²+(2-(-z))²]/3=11/3
由此得出这是一个以11/3为方差的方程
又∵方差公式的性质:(x1+x2+...+xn)/n=x
∴(-x-y-z)/3=2
∴x+y+z=-6