已知x^1,x^2是方程x²-6x+k+1=0的两个实根且x^1²+x^2²=24,则k的值为?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 01:35:04
![已知x^1,x^2是方程x²-6x+k+1=0的两个实根且x^1²+x^2²=24,则k的值为?](/uploads/image/z/15223358-38-8.jpg?t=%E5%B7%B2%E7%9F%A5x%5E1%2Cx%5E2%E6%98%AF%E6%96%B9%E7%A8%8Bx%26%23178%3B-6x%2Bk%2B1%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%A0%B9%E4%B8%94x%5E1%26%23178%3B%2Bx%5E2%26%23178%3B%3D24%2C%E5%88%99k%E7%9A%84%E5%80%BC%E4%B8%BA%3F)
已知x^1,x^2是方程x²-6x+k+1=0的两个实根且x^1²+x^2²=24,则k的值为?
已知x^1,x^2是方程x²-6x+k+1=0的两个实根且x^1²+x^2²=24,则k的值为?
已知x^1,x^2是方程x²-6x+k+1=0的两个实根且x^1²+x^2²=24,则k的值为?
(x1+x2)^2-2x1*x2=24
6^2-2(k+1)=24
36-2k-2=24
2k=10
k=5