已知a²+b²+c²=ab+bc+ca,且a=1.求(a+b-c)²º¹¹的值
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已知a²+b²+c²=ab+bc+ca,且a=1.求(a+b-c)²º¹¹的值
已知a²+b²+c²=ab+bc+ca,且a=1.求(a+b-c)²º¹¹的值
已知a²+b²+c²=ab+bc+ca,且a=1.求(a+b-c)²º¹¹的值
a²+b²+c²=ab+bc+ca
2a²+2b²+2c²=2ab+2bc+2ca
(a-b)²+(a-c)²+(c-b)²=0
a=b=c
(a+b-c)²º¹¹=(a+a-a)²º¹¹=a²º¹¹=1