函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)~函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)上无零点,则实数m的取值范围为?
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![函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)~函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)上无零点,则实数m的取值范围为?](/uploads/image/z/14669389-37-9.jpg?t=%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx%26%23710%3B3%2Bx%26%23710%3B2-x-m%E7%9A%84%E6%9E%81%E5%A4%A7%E5%80%BC%E5%A4%A7%E4%BA%8Ef%EF%BC%88m%EF%BC%89%E4%B8%94f%EF%BC%88x%EF%BC%89%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%880%2C1%EF%BC%89%7E%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx%26%23710%3B3%2Bx%26%23710%3B2-x-m%E7%9A%84%E6%9E%81%E5%A4%A7%E5%80%BC%E5%A4%A7%E4%BA%8Ef%EF%BC%88m%EF%BC%89%E4%B8%94f%EF%BC%88x%EF%BC%89%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%880%2C1%EF%BC%89%E4%B8%8A%E6%97%A0%E9%9B%B6%E7%82%B9%2C%E5%88%99%E5%AE%9E%E6%95%B0m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E4%B8%BA%3F)
函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)~函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)上无零点,则实数m的取值范围为?
函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)~
函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)上无零点,则实数m的取值范围为?
函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)~函数f(x)=xˆ3+xˆ2-x-m的极大值大于f(m)且f(x)在区间(0,1)上无零点,则实数m的取值范围为?
1 f(x)求导 得出极值点 x=1/3 x=-1 通过判断 f(x)在x=-1取得极大值 在x=1/3取得极小值
2 极大值大于f(m) 即f(-1)>f(m) 1
3 因为f(x)在(0,1)内无零点 即无解
也就是 极小值 f(1/3)>0 2
4 解 1 2 会得出m的范围