1)已知x+y=6,xy=-3,则x^2y+xy^=?2)分解因式3(a-b)^2 + 6(b-a)(1)已知x+y=6,xy=-3,则x^2y+xy^=?(2)分解因式3(a-b)^2 + 6(b-a)
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![1)已知x+y=6,xy=-3,则x^2y+xy^=?2)分解因式3(a-b)^2 + 6(b-a)(1)已知x+y=6,xy=-3,则x^2y+xy^=?(2)分解因式3(a-b)^2 + 6(b-a)](/uploads/image/z/14409474-42-4.jpg?t=1%EF%BC%89%E5%B7%B2%E7%9F%A5x%2By%3D6%2Cxy%3D-3%2C%E5%88%99x%5E2y%2Bxy%5E%3D%3F2%EF%BC%89%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F3%EF%BC%88a-b%EF%BC%89%5E2+%2B+6%EF%BC%88b-a%EF%BC%89%EF%BC%881%EF%BC%89%E5%B7%B2%E7%9F%A5x%2By%3D6%EF%BC%8Cxy%3D-3%EF%BC%8C%E5%88%99x%5E2y%2Bxy%5E%3D%3F%EF%BC%882%EF%BC%89%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F3%EF%BC%88a-b%EF%BC%89%5E2+%2B+6%EF%BC%88b-a%EF%BC%89)
1)已知x+y=6,xy=-3,则x^2y+xy^=?2)分解因式3(a-b)^2 + 6(b-a)(1)已知x+y=6,xy=-3,则x^2y+xy^=?(2)分解因式3(a-b)^2 + 6(b-a)
1)已知x+y=6,xy=-3,则x^2y+xy^=?2)分解因式3(a-b)^2 + 6(b-a)
(1)已知x+y=6,xy=-3,则x^2y+xy^=?(2)分解因式3(a-b)^2 + 6(b-a)
1)已知x+y=6,xy=-3,则x^2y+xy^=?2)分解因式3(a-b)^2 + 6(b-a)(1)已知x+y=6,xy=-3,则x^2y+xy^=?(2)分解因式3(a-b)^2 + 6(b-a)
(1)x^2y+xy^2=xy(x+y)=-3*6=-18
(2) 3(a-b)^2 + 6(b-a)= 3(a-b)^2 - 6(a-b)= 3{(a-b)^2 - 2(a-b)}=
3(a-b){(a-b)- 2}=3(a-b)(a-b-2)
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