计算:(a/(a-b)=a^2/a^2-2ab+b^2)÷(a/(a+b)-a^2/a^2-b^2)1.[a/(a-b)=a^2/(a^2-2ab+b^2)]÷[a/(a+b)-a^2/(a^2-b^2)]2.(a-1)[1-(a+1)÷(a-1/a)]3.(-a^2b^3)^3/(ab)^8+b/a^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/28 16:12:44
![计算:(a/(a-b)=a^2/a^2-2ab+b^2)÷(a/(a+b)-a^2/a^2-b^2)1.[a/(a-b)=a^2/(a^2-2ab+b^2)]÷[a/(a+b)-a^2/(a^2-b^2)]2.(a-1)[1-(a+1)÷(a-1/a)]3.(-a^2b^3)^3/(ab)^8+b/a^2](/uploads/image/z/14248438-70-8.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%28a%2F%28a-b%29%3Da%5E2%2Fa%5E2-2ab%2Bb%5E2%29%C3%B7%28a%2F%28a%2Bb%29-a%5E2%2Fa%5E2-b%5E2%291.%5Ba%2F%28a-b%29%3Da%5E2%2F%28a%5E2-2ab%2Bb%5E2%29%5D%C3%B7%5Ba%2F%28a%2Bb%29-a%5E2%2F%28a%5E2-b%5E2%29%5D2.%28a-1%29%5B1-%28a%2B1%29%C3%B7%28a-1%2Fa%29%5D3.%28-a%5E2b%5E3%29%5E3%2F%28ab%29%5E8%2Bb%2Fa%5E2)
计算:(a/(a-b)=a^2/a^2-2ab+b^2)÷(a/(a+b)-a^2/a^2-b^2)1.[a/(a-b)=a^2/(a^2-2ab+b^2)]÷[a/(a+b)-a^2/(a^2-b^2)]2.(a-1)[1-(a+1)÷(a-1/a)]3.(-a^2b^3)^3/(ab)^8+b/a^2
计算:(a/(a-b)=a^2/a^2-2ab+b^2)÷(a/(a+b)-a^2/a^2-b^2)
1.[a/(a-b)=a^2/(a^2-2ab+b^2)]÷[a/(a+b)-a^2/(a^2-b^2)]
2.(a-1)[1-(a+1)÷(a-1/a)]
3.(-a^2b^3)^3/(ab)^8+b/a^2
计算:(a/(a-b)=a^2/a^2-2ab+b^2)÷(a/(a+b)-a^2/a^2-b^2)1.[a/(a-b)=a^2/(a^2-2ab+b^2)]÷[a/(a+b)-a^2/(a^2-b^2)]2.(a-1)[1-(a+1)÷(a-1/a)]3.(-a^2b^3)^3/(ab)^8+b/a^2
1.(a+b)/(a-b)
2.(a-1)[1-(a+1)÷(a-1/a)]=(a-1)(1-a/(a-1))=-1
3.(-a^2b^3)^3/(ab)^8+b/a^2=-b/a^2+b/a^2=0
第一题=是什么意思?
2 .(a-1)[1-(a+1)÷(a-1/a)]=(a-1)[1-a(a+1)/(a²-1)]=(a-1)[1-a/(a-1)]=(a-1)[-1/(a-1)]=-1
3 .(-a^2b^3)^3/(ab)^8+b/a^2=-b/a²+b/a²=0
CNM
1 (a+b)/(a-b)
2 -1
3 0