已知m²+n²=5,x²+y²=41,求多项式(mx+ny)²+(nx-my)²的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 21:11:18
![已知m²+n²=5,x²+y²=41,求多项式(mx+ny)²+(nx-my)²的值](/uploads/image/z/13555229-5-9.jpg?t=%E5%B7%B2%E7%9F%A5m%26%23178%3B%2Bn%26%23178%3B%3D5%2Cx%26%23178%3B%2By%26%23178%3B%3D41%2C%E6%B1%82%E5%A4%9A%E9%A1%B9%E5%BC%8F%28mx%2Bny%29%26%23178%3B%2B%28nx-my%29%26%23178%3B%E7%9A%84%E5%80%BC)
已知m²+n²=5,x²+y²=41,求多项式(mx+ny)²+(nx-my)²的值
已知m²+n²=5,x²+y²=41,求多项式(mx+ny)²+(nx-my)²的值
已知m²+n²=5,x²+y²=41,求多项式(mx+ny)²+(nx-my)²的值
(mx+ny)²+(nx-my)²
=(mx)²+(ny)²+(nx)²+(my)²
=x²(m²+n²)+y²(n²+m²)
=(x²+y²)(m²+n²)
=41*5
=205