(ab+1)²-(a+b)²2(a²-3bc)+a(4b-3c)4x²+1/4-9y²-2x4a的四次方-a²-1a-25清楚些啊,
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 05:05:50
![(ab+1)²-(a+b)²2(a²-3bc)+a(4b-3c)4x²+1/4-9y²-2x4a的四次方-a²-1a-25清楚些啊,](/uploads/image/z/12970019-11-9.jpg?t=%EF%BC%88ab%2B1%EF%BC%89%26%23178%3B-%EF%BC%88a%2Bb%EF%BC%89%26%23178%3B2%EF%BC%88a%26%23178%3B-3bc%EF%BC%89%2Ba%EF%BC%884b-3c%EF%BC%894x%26%23178%3B%2B1%2F4-9y%26%23178%3B-2x4a%E7%9A%84%E5%9B%9B%E6%AC%A1%E6%96%B9-a%26%23178%3B-1a-25%E6%B8%85%E6%A5%9A%E4%BA%9B%E5%95%8A%2C)
(ab+1)²-(a+b)²2(a²-3bc)+a(4b-3c)4x²+1/4-9y²-2x4a的四次方-a²-1a-25清楚些啊,
(ab+1)²-(a+b)²
2(a²-3bc)+a(4b-3c)
4x²+1/4-9y²-2x
4a的四次方-a²-1a-25
清楚些啊,
(ab+1)²-(a+b)²2(a²-3bc)+a(4b-3c)4x²+1/4-9y²-2x4a的四次方-a²-1a-25清楚些啊,
七年级,这个应该不是求值吧,是因式分解吗?
(ab+1)^2-(a+b)^2
=(ab+1+a+b)(ab+1-a-b)
=[a(b+1)+(b+1)][a(b-1)-(b-1)]
=(a+1)(b+1)(a-1)(b-1)
a^2+bc=1b^2-2bc=-6 3a^2+4b^2-5bc=3a^2+3bc-3bc+4b^2-5bc=3a^2+3bc+4b^2-8bc=3(a^2+bc)+4(b^2-2bc)=3*1+4*(-6)=3-24=-21
(ab+1)^2-(a+b)^2
=(ab+1+a+b)(ab+1-a-b)
=[a(b+1)+(b+1)][a(b-1)-(b-1)]
=(a+1)(b+1)(a-1)(b-1)
是要干嘛????