分解因式1 (x^+3x-3)(x^+3x+4)-8计算(1+2)(1+2^)(1+2^^).(1+2^^^)(1+2^^^^)+1(^为二次^^为四次^^^为八次 以此类推
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![分解因式1 (x^+3x-3)(x^+3x+4)-8计算(1+2)(1+2^)(1+2^^).(1+2^^^)(1+2^^^^)+1(^为二次^^为四次^^^为八次 以此类推](/uploads/image/z/12879649-1-9.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F1+%EF%BC%88x%5E%2B3x-3%EF%BC%89%28x%5E%2B3x%2B4%29-8%E8%AE%A1%E7%AE%97%EF%BC%881%2B2%EF%BC%89%EF%BC%881%2B2%5E%EF%BC%89%281%2B2%5E%5E%29.%281%2B2%5E%5E%5E%29%281%2B2%5E%5E%5E%5E%29%2B1%EF%BC%88%5E%E4%B8%BA%E4%BA%8C%E6%AC%A1%5E%5E%E4%B8%BA%E5%9B%9B%E6%AC%A1%5E%5E%5E%E4%B8%BA%E5%85%AB%E6%AC%A1+%E4%BB%A5%E6%AD%A4%E7%B1%BB%E6%8E%A8)
分解因式1 (x^+3x-3)(x^+3x+4)-8计算(1+2)(1+2^)(1+2^^).(1+2^^^)(1+2^^^^)+1(^为二次^^为四次^^^为八次 以此类推
分解因式
1 (x^+3x-3)(x^+3x+4)-8
计算
(1+2)(1+2^)(1+2^^).(1+2^^^)(1+2^^^^)+1
(^为二次^^为四次^^^为八次 以此类推
分解因式1 (x^+3x-3)(x^+3x+4)-8计算(1+2)(1+2^)(1+2^^).(1+2^^^)(1+2^^^^)+1(^为二次^^为四次^^^为八次 以此类推
(x^2+3x-3)(x^2+3x+4)-8
=(x^2+3x)^2+(x^2+3x)-20
=(x^2+3x-4)(x^2+3x+5)
=(x^2+3x+5)(x-1)(x+4)
(1+2)(1+2^)(1+2^^).(1+2^^^)(1+2^^^^)+1
=(2+1)(2^2+1)(2^4+1).(2^8+1)(2^16+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1).(2^8+1)(2^16+1)+1
=(2^2-1)(2^2+1)(2^4+1).(2^8+1)(2^16+1)+1
=(2^4-1)(2^4+1).(2^8+1)(2^16+1)+1
=(2^8-1)(2^8+1)(2^16+1)+1
=(2^16-1)(2^16+1)+1
=2^32-1+1
=2^32
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