1+1/√2+1/√3+1/√4+……+1/√N的值从第几项开始大于3?
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![1+1/√2+1/√3+1/√4+……+1/√N的值从第几项开始大于3?](/uploads/image/z/12690955-19-5.jpg?t=1%2B1%2F%E2%88%9A2%2B1%2F%E2%88%9A3%2B1%2F%E2%88%9A4%2B%E2%80%A6%E2%80%A6%2B1%2F%E2%88%9AN%E7%9A%84%E5%80%BC%E4%BB%8E%E7%AC%AC%E5%87%A0%E9%A1%B9%E5%BC%80%E5%A7%8B%E5%A4%A7%E4%BA%8E3%3F)
1+1/√2+1/√3+1/√4+……+1/√N的值从第几项开始大于3?
1+1/√2+1/√3+1/√4+……+1/√N的值从第几项开始大于3?
1+1/√2+1/√3+1/√4+……+1/√N的值从第几项开始大于3?
s=1+1/√2+1/√3+1/√4+……+1/√n
=2/(√1+√1)+2/(√2+√2)+2/(√3+√3)+……+2/[√n+√n]
>2/(√2+√1)+2/(√3+√2)+2/(√4+√3)+……+2/[√n+√(n-1)]
=2*[(√2-√1)+(√3-√2)+(√4-√3)+……+[√n-√(n-1)]
=2*(-1+√n)>3
√n>2.5
n>6.25
所以n=7
√2+1分之1+√3+√2分之1+√4+√3分之1+……+√2004+√2003分之1=?
1/1+√2+1/√2+√3+…+1/√2013+√2014=
化简:[1/(2+√2)]+[1/(3√2)]+[1/(4√3+3√4]+……+[1/10√9+9√10]化简这个式,/是除号,√是根号[1/(2+√2)]+[1/(3√2)]+[1/(4√3+3√4]+……+[1/10√9+9√10][1/(2+√2)]+[1/(3√2+2√3)]+[1/(4√3+3√4)]+……+[1
/√1-√2/+/√2-√3/+…+/√99-√100/
计算:1/(1+√2)+1/(√2+√3)+1/(√3+√4)+…+1/(√8+√9)
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0-1/(√1+√0)-1/(√2+√1)-1/(√3+√2)+……+1/(√100-√99)
1+1/√1+1/√2+1/√3+1/√4+……+1/√(10^6)=?(结果取整)结果只要整数部分.
化简1/√2+1+1/√3+√2+……+1/√10+√9急速
“1/1+√2+1/√2√3+1/√3+√4+……+1/√98+√99+1/√99+√100”怎么化简?
(2√1+1√2)/1+(3√2+2√3)/1+(1+4√3+3√4)/1+……(10√9+9√10)/1=?反了1/(2√1+1√2)+1/(3√2+2√3)+1/(1+4√3+3√4)+……1/(10√9+9√10)
关于根式的数列1/(2√1+√2)+1/(3√2+2√3)1/(4√3+3√4)……+1/100√99+99√100
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求1/(√2+1)+1/(√3+√2)+…+1/(√n+√n-1)的值?
(1+√2)分之2+(√2+√3)分之2+(√3+√4)分之2+…+(√99+√100)分之2=?
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化简 1) √[(1998*1999*2000*2001+1)/4] 2) 1/(2√1+1√2)+1/(3√2+2√3)+……+1/(100√99+99√100)化简 1) √[(1998*1999*2000*2001+1)/4] 2) 1/(2√1+1√2)+1/(3√2+2√3)+……+1/(100√99+99√100)