y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=10值?需要简单过程,先谢啦有才人士多帮忙啊
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/27 04:55:38
![y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=10值?需要简单过程,先谢啦有才人士多帮忙啊](/uploads/image/z/1268848-64-8.jpg?t=y%3D%28x-1%29%28x-2%29%28x-3%29%28x-4%29%28x-5%29%28x-6%29%28x-7%29%28x-8%29%28x-9%29%28x-10%29%E7%9A%84%E5%AF%BC%E6%95%B0%E5%9C%A8x%3D10%E5%80%BC%3F%E9%9C%80%E8%A6%81%E7%AE%80%E5%8D%95%E8%BF%87%E7%A8%8B%2C%E5%85%88%E8%B0%A2%E5%95%A6%E6%9C%89%E6%89%8D%E4%BA%BA%E5%A3%AB%E5%A4%9A%E5%B8%AE%E5%BF%99%E5%95%8A)
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=10值?需要简单过程,先谢啦有才人士多帮忙啊
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=10值?
需要简单过程,先谢啦有才人士多帮忙啊
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=10值?需要简单过程,先谢啦有才人士多帮忙啊
设a=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)
那么y=a*(x-10);
那么y^=a^*(x-10)+a*(x-10)^=a^*(x-10)+a
那么y^|10=a^*(10-10)+a=9!
第二种方法是两边同时去取对数,将盛变成加 这样在求导数就好求了,最后再化成y的导数
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)
y'={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)+{(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
y'(10)={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
=x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)
(x=10)