1+(1+ⅰ)+(1+ⅰ)²+(1+ⅰ)³+.+.(1+ⅰ)n-1=多少 (n-1是次方)
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![1+(1+ⅰ)+(1+ⅰ)²+(1+ⅰ)³+.+.(1+ⅰ)n-1=多少 (n-1是次方)](/uploads/image/z/1267229-29-9.jpg?t=1%2B%EF%BC%881%2B%E2%85%B0%EF%BC%89%2B%EF%BC%881%2B%E2%85%B0%EF%BC%89%26%23178%3B%2B%EF%BC%881%2B%E2%85%B0%EF%BC%89%26%23179%3B%2B.%2B.%281%2B%E2%85%B0%29n-1%3D%E5%A4%9A%E5%B0%91+%EF%BC%88n-1%E6%98%AF%E6%AC%A1%E6%96%B9%EF%BC%89)
1+(1+ⅰ)+(1+ⅰ)²+(1+ⅰ)³+.+.(1+ⅰ)n-1=多少 (n-1是次方)
1+(1+ⅰ)+(1+ⅰ)²+(1+ⅰ)³+.+.(1+ⅰ)n-1=多少 (n-1是次方)
1+(1+ⅰ)+(1+ⅰ)²+(1+ⅰ)³+.+.(1+ⅰ)n-1=多少 (n-1是次方)
1+(1+ⅰ)+(1+ⅰ)²+(1+ⅰ)³+.+.(1+ⅰ)^(n-1)=
=[(1+ⅰ)^n-1]/(1+i-1)=[(1+ⅰ)^n-1]/i=i-i(1+ⅰ)^n